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How use distinct and top together in SQL?
It works simply if you use query like this: SELECT DISTINCT TOP 2 name FROM [ATTENDANCE] ; In the above query, name is the column_name and [ATTENDANCE] is the table_name. You can also use WHERE with this to make filtering conditions.
How do you use distinct and order by in the same select statement?
If we add the DISTINCT operation, it would be added between SELECT and ORDER BY :
- FROM MonitoringJob.
- SELECT Category, CreationDate.
- DISTINCT.
- ORDER BY CreationDate DESC.
- SELECT Category.
How to select distinct on just one column?
How can I SELECT DISTINCT on just one column? The simplest solution would be to use a subquery for finding the minimum ID matching your query. In the subquery you use GROUP BY instead of DISTINCT: SELECT t.* FROM TestData t INNER JOIN (SELECT MIN (ID) as MinID FROM TestData WHERE SKU LIKE ‘FOO-%’ ) dt ON t.ID=dt.MinID
Can a SELECT statement return distinct rows in SQL?
So, in this case, the statement will return distinct rows for FirstName and LastName. Unfortunately there is no direct way to use DISTINCT on one set of fields and display others. Once you add columns to the SELECT statement they become under the influence of the DISTINCT operator.
How do the distinct and top Select clauses work together?
Unfortunately there is no direct way to use DISTINCT on one set of fields and display others. Once you add columns to the SELECT statement they become under the influence of the DISTINCT operator. I say direct, as you could get a distinct list, and then use a INNER JOIN to pull in other columns.
How to select only one row for each distinct email address?
This will select only one row for each distinct email address, the row with the minimum id which is what your result seems to portray Try this – you need a CTE (Common Table Expression) that partitions (groups) your data by distinct e-mail address, and sorts each group by ID – smallest first.