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How to take the record with the Max date?
If date and col_date are the same columns you should simply do: SELECT t.* FROM TABLENAME t JOIN ( SELECT A, MAX (col_date) AS col_date FROM TABLENAME GROUP BY A ) m ON m.A = t.A AND m.col_date = t.col_date Since Oracle 12C, you can fetch a specific number of rows with FETCH FIRST ROW ONLY .
How to find records with the most recent date?
If you want to return the records with the most recent or latest dates in a field, and you do not know the exact date values, or they don’t matter, you create a top values query. If you want to return all the records where the date matches, is prior to, or later than a specific date, you use a filter.
How to select only the records with the highest date in LINQ?
How can I, in LINQ to SQL, only get the last lasttrace of every AccountId (the one with the highest date)? var q = from n in table group n by n.AccountId into g select g.OrderByDescending (t=>t.Date).FirstOrDefault ();
How to query SQL for a latest record date?
Select * from table1 where lastest_date= (select Max (latest_date) from table1 where user=yourUserName) Inner Query will return the latest date for the current user, Outer query will pull all the data according to the inner query result.
How to get the maximum Ord date in SQL?
To get the maximum ‘ord_date’ from the ‘orders’ table, the following SQL statement can be used : SELECT MAX (ord_date) AS “Max Date” FROM orders; Output: Max Date —– 20-OCT-08 SQL MAX() on date value with where . To get data of ‘ord_num’, ‘ord_amount’, ‘ord_date’, ‘agent_code’ from the ‘orders’ table with the following conditions –
How to use max ( ) function on date?
MAX() function on date. In this part, you will see the usage of SQL MAX() function on date type of the column of a table. Example: Sample table: orders. To get the maximum ‘ord_date’ from the ‘orders’ table, the following SQL statement can be used : SELECT MAX (ord_date) AS “Max Date” FROM orders;
How to select group from table with Max date?
SELECT group, date, checks FROM ( SELECT *, max_date = MAX(date) OVER (PARTITION BY group) FROM table ) AS s WHERE date = max_date ; to get the desired result. Basically, this is similar to @Twelfth’s suggestion but avoids a join and may thus be more efficient.