How to include a PHP variable inside a MySQL statement?

How to include a PHP variable inside a MySQL statement?

The rules of adding a PHP variable inside of any MySQL statement are plain and simple: Any variable that represents an SQL data literal, (or, to put it simply – an SQL string, or a number) MUST be added through a prepared statement.

Is there a placeholder for PHP in MySQL?

For the limited set of placeholders you can use PDO. Though for real life usage you will need extended set which is offered by but a few libraries, one of which is SafeMysql.

Can a variable be added to a SQL statement?

Any variable that represents an SQL data literal, (or, to put it simply – an SQL string, or a number) MUST be added through a prepared statement. No exceptions.

How to add a variable to a query?

But if you’re going to add the variable in another part of a query, the rules change. To add a number, you have to cast it to its type explicitly. $limit = intval ($_GET [‘limit’]); //casting to int type! $query = “SELECT * FROM table LIMIT $limit”;

How to create a variable in a SQL query?

Don’t build SQL queries by mashing together strings though. Use prepared statements and parameterized queries. $result = mysql_query (“SELECT * FROM animals WHERE hand= ” .$_SESSION [‘SESS_HAND’]. “); Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question.

How to create a dynamic mysql query using PHP?

I have an html table that loads everything in a mySQL database table. I have dropdowns that relate to columns of that mySQL table – when the user selects one of the dropdowns it uses AJAX to query the database.

Why does MySQL not work with empty variables?

Which you can imagine doesn’t work because if any of those fields are empty – the query fails (or returns nothing, rather). Obviously creating such a ‘static’ query like that really makes it difficult if certain variables are empty.