How to correctly set a date variable value?

How to correctly set a date variable value?

DECLARE @sp_Date DATETIME SET @sp_Date = DateAdd (m, -6, GETDATE ()) SELECT DISTINCT pat.PublicationID FROM PubAdvTransData AS pat INNER JOIN PubAdvertiser AS pa ON pat.AdvTransID = pa.AdvTransID WHERE (pat.LastAdDate > @sp_Date) AND (pa.AdvertiserID = 12345))

How do you create a date variable in Q?

The most straightforward way to create a Date Variable is to change a variable’s Variable Type to Date in the Variables and Questions tab. If it is a Text Variable Q will automatically insert a new Date Variable underneath.

How does a date variable work in VBA?

The Date Variable works exactly the same in Access VBA as in Excel VBA. This procedure demonstrates how to create a date variable and update a field in an access table with the value.

Do you need to define date variables in SPSS?

It is important to specify which variables in your data are dates/ times so that SPSS can recognize and use these variables appropriately. However, the procedure for defining a variable as date/time depends on its currently defined type (e.g., string, numeric, date/time).

Can a view have parameters in SQL Server?

Views cannot have parameters – either you need to return everything (and then use the parameters on the select from that view), or you need to convert it into a table-valued stored function – marc_s Jul 16 ’12 at 13:03.

Is it possible to set variable inside a view in SQL Server?

No. You can’t do that in a view. I’m not even sure what the point of the above view would be since it doesn’t return any value. Even if you could, you wouldn’t want to. A variable like this can only store one varchar (20) value.

Can you create a parametrized view in SQL Server?

You cannot create a parametrized view atleast in SQL server rather use a table function. Please refer Create parameterized VIEW in SQL Server 2008 for more details. Hope it will give you an idea. View with Parameter is possible as per following info. Please visit following link: Thanks for contributing an answer to Stack Overflow!