Contents
What happens if the center of the ball is inside a brick?
If the center of the ball is inside the coordinates of one of our bricks, we’ll change the direction of the ball. For the center of the ball to be inside the brick, all four of the following statements need to be true: The x position of the ball is greater than the x position of the brick.
How to check for collision in drawbricks?
Update your drawBricks () function as follows: Now we need to involve the brick status property in the collisionDetection () function: if the brick is active (its status is 1) we will check whether the collision happens; if a collision does occur we’ll set the status of the given brick to 0 so it won’t be painted on the screen.
Why are the bricks staying where they are?
The problem is that the bricks are staying where they are. We have to figure out a way to get rid of the ones we’ve already hit with the ball. We can do that by adding an extra parameter to indicate whether we want to paint each brick on the screen or not.
Is the ball contained within a brick Java?
Second answer (in addition to other answer which I believe is ALSO a problem), your logic is asking if the ball is contained within a brick, but when you create the ball its radius is greater than the height of a brick, so even correcting that logic won’t fix the problem.
What happens when an object hits a wall?
The wall doesn’t move, but the object moves in the opposite direction. Assume this is an ideal, elastic collision. I have a feeling this is wrong, so anybody clarify this for me? Yes, it is wrong. You are wrong if you think that in an ideal, elastic collision the velocity of the bouncing object is exactly the same.
Which is greater the X or the Y position of the ball?
The x position of the ball is less than the x position of the brick plus its width. The y position of the ball is greater than the y position of the brick. The y position of the ball is less than the y position of the brick plus its height.