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When to use const in function parameters?
const is pointless when the argument is passed by value since you will not be modifying the caller’s object. const should be preferred when passing by reference, unless the purpose of the function is to modify the passed value.
Why use const in function parameters c++?
C++ solution: constant parameters. When you put “const” in front of a parameter, it means that it cannot be modified in the function. (In other words, you’ll get a compile-time error if you try to assign to it.) These are useful for giving meaningful names to things, such as intermediate Page 3 results.
When to use const on parameters passed by a reference?
Using const only on parameters passed by reference or pointer has the additional benefit of making it really obvious which parameters are pointers or references. It’s one more thing to stick out and say “Watch out! Any param with const next to it is a reference or pointer!”.
When do you use const in a Param?
When dealing with pointers or references, however, const is critically important when needed, and must be used, as it prevents undesired side effects with persistent changes outside the function, and therefore every single pointer or reference must use const when the param is an input only, not an output.
Why do you put const on the b parameter?
Putting const on the boolean b parameter in your example only puts a constraint on the implementation and doesn’t contribute for the class’s interface (although not changing parameters is usually advised). The function signature for is the same, which explains your .c and .h
When to use const in a function signature?
The reason is that const for the parameter only applies locally within the function, since it is working on a copy of the data. This means the function signature is really the same anyways. It’s probably bad style to do this a lot though. I personally tend to not use const except for reference and pointer parameters.