Which is the correct way to rotate y axis?

Which is the correct way to rotate y axis?

If you rotate y=f (x) about the y axis, you should use shell. Of course, you can always use both methods if you can find the inverse of the function. If I wanted to rotate y=x^2 about the y axis, that would be equivalent to rotating x=√ (y) about the x axis.

Can a cylinder rotate on a fixed axis?

To do so I want to have cylinders rotate on the z-axis, and only the z-axis. How would I do that? You can use the transform.Rotate method to rotate an object around a fixed axis.

When to use shell or disk for y axis?

It really depends on the situation you have. If you have a function y=f (x) and you rotate it about the x axis, you should use disk (or ring, same thing in my mind). If you rotate y=f (x) about the y axis, you should use shell.

How to rotate GameObject on only one axis?

Well, it was rather hard to rotate GameObject ONLY in one axis, nothing worked correctly, adding values to another axis, even RotateAround or Rotate, but… dx, dy, dz – how much you want to change value in degrees.

How to find the volume of a figure that is rotated around the Y axis?

Finding the volume of a figure that is rotated around the y-axis using the disc method. Created by Sal Khan. This is the currently selected item. Posted 8 years ago. Direct link to Blu Jay’s post “How will I know if I’ll use the disk, ring or shel…” How will I know if I’ll use the disk, ring or shell method?

Why is it 1 to 4 around the Y axis?

Direct link to Stefen’s post “See 0:12 – it is 1 to 4 because that is how he dec…” – it is 1 to 4 because that is how he decided to define the shape of the object whose volume is being measured. Comment on Stefen’s post “See 0:12 – it is 1 to 4 because that is how he dec…” Posted 8 years ago.

Why does the disc rotate around the Y axis?

He did that because he is rotating around the y-axis and he is trying to find the volume. As Sal showed, you need to find the radius of each disk so as to apply it into A = (pi)r^2 and then V = A (dy). Notice that it is in terms of dy, not dx.