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Is moving-average weakly stationary?
The mean and variance of any MA(q ) process are finite and constant, while the autocorrelation function is finite and does not depend on t . Therefore any MA(q ) is weakly stationary.
Is a finite order MA process is always weakly stationary?
The moving-average model specifies that the output variable depends linearly on the current and various past values of a stochastic (imperfectly predictable) term. Contrary to the AR model, the finite MA model is always stationary.
Why is Ma model always stationary?
However, an MA(q) process will be strongly stationary because any n-element vector within a sequence generated by an MA(q) process will have the same joint distribution.
What is a weakly stationary process?
Weak-Sense Stationary Processes: A random process is called weak-sense stationary or wide-sense stationary (WSS) if its mean function and its correlation function do not change by shifts in time.
Is Ma 1 weakly stationary?
MA(1) is also strictly stationary as both P(Xt1,…,Xtn) and P(Xt1+k,…,Xtn+k) multivariate (1-dependent) Normal distributions with identical parameters as it is a combination of WN random variables. In general, all weakly stationary Gaussian processes are strictly stationary too.
Why is a moving average process stated as stationary?
Because, although, the mean will remain the same for Yt and Yt+k, the variance and co-variance will change if you calculate for Yt+k, so in that case, why is it stated as stationary? Can anyone explain: how do you know if a moving average process is weakly stationary, strictly stationary or non stationary?
How is the memory of a moving average process limited?
Thus, its memory is limited to one step into the future; beyond that, it starts anew. The model for a moving-average process says that at time t the data value, Yt, consists of a constant, μ, plus random noise, ɛt, minus a fraction, θ (theta, the moving-average coefficient), of the previous random noise.
Why is a moving average process not random?
Because it has memory, a moving-average process can produce adjacent pairs of observations that are more likely to both be either high or low. However, because its memory is limited, the series is random again after only two steps. The result is a series that is not quite as random as a pure random noise series.
What does weakly stationarity of autocovariance mean?
Think of what weakly stationarity means. It means that the expected value of the process is finite and constant. It also means that the autocovariance does not depend on where two random variables are positioned but just on their distance! Autocovariance between today and yesterday same as autocovariance between 100 days and 101 days ago.