Contents
Do eigenvectors have to be unit vectors?
Most libraries (including numpy) will return eigenvectors that have been scaled to have a length of 1 (called unit vectors). Eigenvalue λ tells us how much x is scaled, stretched, shrunk, reversed or untouched when multiplied by A. So, a set of 2D vectors will have at most 2 eigenvalues and corresponding eigenvectors.
Are eigenvectors unit length?
A nonzero scalar multiple of an eigenvector is equivalent to the original eigenvector. Hence, without loss of generality, eigenvectors are often normalized to unit length.
How to find the length of the projection of the vector?
Hint: find a unit vector in the direction of the line and construction its projection operators. Hint. Your line is parallel to the vector , the unit vector along which is . The projection of vector along is given by . To get the length of the projection of this vector on the line yes you first get a unit directing vector to the line.
How to find the unit vector along a line?
To find a unit vector which points along the line, we find two different vectors which point to different points on the line, take their difference, and then normalise the result. Finding two different vectors which point to the line is the same as finding two different outputs of .
How are vector length and angle between vectors generalized?
Since the notions of vector length and angle between vectors can be generalized to any n-dimensional inner product space, this is also true for the notions of orthogonal projection of a vector, projection of a vector onto another, and rejection of a vector from another. In some cases, the inner product coincides with the dot product.
When does a vector projection have a negative sign?
The scalar projection a on b is a scalar which has a negative sign if 90 degrees < θ ≤ 180 degrees. It coincides with the length ‖ c ‖ of the vector projection if the angle is smaller than 90°. More exactly: a1 = −‖ a1 ‖ if 90° < θ ≤ 180°. The vector projection of a on b is a vector a1 which is either null or parallel to b. More exactly: