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How do I replace a non-breaking space with regular space?
The quick answer is that yes, there is a keyboard shortcut for non-breaking spaces: it is Ctrl+Shift+Spacebar….Follow these steps:
- Press Ctrl+H to display the Replace tab of the Find and Replace dialog box.
- In the Find What box, enter “^-” (without the quote marks).
What is 0xA0 character?
Unicode Character “ ” (U+00A0)
| Name: | No-Break Space (NBSP) |
|---|---|
| Character is Mirrored: | No |
| GCGID: | SP300000 |
| HTML Entity: | &NonBreakingSpace |
| UTF-8 Encoding: | 0xC2 0xA0 |
What character is ascii 160?
There is, however, another type of “space” character known as a non-breaking space that is represented by the ASCII code number 160.
How do I remove weird spaces in word?
Change the spacing between characters
- Select the text that you want to change.
- On the Home tab, click the Font Dialog Box Launcher, and then click the Advanced tab.
- In the Spacing box, click Expanded or Condensed, and then specify how much space you want in the By box.
What character is 0x02?
ASCII Table, ISO 1252 Latin-1 Chart & Character Set
| Char | Dec | Hex |
|---|---|---|
| ^A | 1 | 0x01 |
| ^B | 2 | 0x02 |
| ^C | 3 | 0x03 |
| ^D | 4 | 0x04 |
How to replace non breaking space with normal space?
The code below uses a regular expression to replace non breaking spaces with normal spaces. This will replace the non breaking space with normal space. I’d suggest creating your own string comparer that extends one of the original ones — do the “normalization” there (replace non-breaking space with regular space).
How to replace whitespace characters in a string?
But you can simply replace () that characters with a space, and then call trim (), so you keep the spaces that are ‘inside’ your string. There are three non-breaking whitespace characters that are excluded from the Character.isWhitespace () method : \00A0, \ and, \, so you probably want to replace those too.
How to compare strings to non breaking space?
The strings are pulled in from a variety of sources (including user input) and are then compared. However I’m running into problems when comparing space ’32’ to non-breaking space ‘160’.
How to trim NO BREAK SPACE in Java?
While is a non breaking space (a space that does not want to be treated as whitespace), you can trim a string while preserving every within the string with a simple regex: string.replaceAll (” (^\\h*)| (\\h*$)”,””) h is a horizontal whitespace character: [ txA0u1680u180eu2000-u200au202fu205fu3000]