How can I have a variable field width with printf?

How can I have a variable field width with printf?

You can also use a * for the precision: printf(“%*. *f”, width, precision, value); Note that both width and precision must have type int as expected by printf for the * arguments, type size_t is inappropriate as it may have a different size and representation on the target platform.

Can you use a variable in printf?

1 Answer. printf formats can use variable arguments for the width and precision parameters: printf(“%*s\n”, width, str); will output the string right aligned on width characters, with leading spaces.

What does %% mean in printf?

format escape sequence
% indicates a format escape sequence used for formatting the variables passed to printf() . So you have to escape it to print the % character.

What is a field width?

Field width is number of characters/numbers prescribed for both input and output data variables.

What is field width specification?

The width specification consists of characters between the % and the type field specifier, which may include a positive integer called the width field and one or more characters indicating the size of the field, which may also be considered as modifiers of the type of the field, such as an indication of whether the …

Why is the use of printf?

The printf() function is used for output. It prints the given statement to the console. The syntax of printf() function is given below: printf(“format string”,argument_list);

Whats a field size?

(fēld sīz) The projection that, on a plane perpendicular to the beam axis of the light field, corresponds to the area being treated by radiation. Synonym(s): portal (3) .

What’s the variable format for printf in Bash?

In the script that you posted, width has been assigned the value 55, so that both $width and $ {width} are expanded by bash to 55: the entire first parameter to printf expands to %55.55s ; this is the format %s, with a field width and precision specifiers that ask to print on exactly 55 characters.

How do you find the field width in printf?

A field width or precision, or both, may be indicated by an asterisk ‘∗’ or an asterisk followed by one or more decimal digits and a ‘$’ instead of a digit string. In this case, an int argument supplies the field width or precision.

Do you have to have INT for precision in printf?

Note that both width and precision must have type int as expected by printf for the * arguments, type size_t is inappropriate as it may have a different size and representation on the target platform.

How to store a formatted string in C?

I want to store a formatted string using something similar to what printf does in C. The latter is an error obviously. You can do it with sprintf, but not alone (safely). On a sane system, use snprintf twice, once to find out the size to use and the second time to actually do it.