How to extract 5 digits from filename in Bash?

How to extract 5 digits from filename in Bash?

Given a filename in the form someletters_12345_moreleters.ext, I want to extract the 5 digits and put them into a variable. So to emphasize the point, I have a filename with x number of characters then a five digit sequence surrounded by a single underscore on either side then another set of x number of characters.

How to remove non-numeric characters from a string in Bash?

How to remove all non-numeric characters from a string in Bash? How can I edit the string file such that it only contains the numbers and the text part is removed? should print 123 only. Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question. Provide details and share your research! But avoid …

How to extract numbers from a string in Linux?

(Note that in the expression above, [^0-9] may look like a regex atom, but it is not.) You can read about this form or Parameter Expansion in the bash man page. Note that $ {string//this/that} (as well as the <<<) is a bashism, and is not compatible with traditional Bourne or posix shells.

How to extract a part of a variable in Bash?

Both solutions presented are pure bash, with no process spawning involved, hence very fast. JB. JB. Generic solution where the number can be anywhere in the filename, using the first of such sequences: Another solution to extract exactly a part of a variable:

How to extract the portion between the last hyphen?

To extract the portion in between the last hyphen and the next-to-last one, you could use the following script (provide the strings/files as command line arguments):

Which is the default substring indexing in Bash?

Substring indexing is zero-based unless the positional parameters are used, in which case the indexing starts at 1 by default. If offset is 0, and the positional parameters are used, $0 is prefixed to the list. I’m surprised this pure bash solution didn’t come up: