How to pass a variable in curl command in shell?

How to pass a variable in curl command in shell?

The variable job_id has a value in it, say, 1160. When I execute the curl command in shell it gives me the following error: {“message”:”Sorry.

What happens when I run curl in shell?

When I execute the curl command in shell it gives me the following error: {“message”:”Sorry. An unexpected error occured.”, “stacktrace”:”Bad Request. The request could not be understood by the server due to malformed syntax.”} If I pass the number ‘1160’ directly in the command, as shown below, the curl command works.

How to use double quotes in curl script?

You can use double quotes instead. http://tldp.org/LDP/abs/html/quoting.html I realize now you are closing all your single quotes before and re-opening them after your variables but the variables are still probably being read incorrectly because they aren’t quoted.

Can you use single quotes in a bash variable?

When using variables in shell, you can only use doubles quotes, not single quotes : the variables inside single quotes are not expanded. Learn the difference between ‘ and ” and `. See http://mywiki.wooledge.org/Quotes and http://wiki.bash-hackers.org/syntax/words

What are curl command line URL parameters for work?

Q&A for work Connect and share knowledge within a single location that is structured and easy to search. Learn more CURL Command Line URL Parameters Ask Question Asked8 years, 8 months ago Active3 months ago Viewed523k times 211 28

Do you use$ on variables in curl?

In the shell, unlike Perl or PHP or global variables in Ruby, you don’t use the $ on variables when assigning them, but only when referencing them: But that still leaves the problem of the literal quotation marks in the curl command.

How to delete curl parameters from form body?

Unless the request handler expects the parameters coming from form body. Try it out: curl -X DELETE “http://localhost:5000/locations?id=3”

How is the variable generated in a curl statement?

Each cURL statement relies on a variable generated from a cuRL statement executed before it. I’m trying to figure out the smartest way to go about this. Here is the first cURL statement; However, in the next cURL statement, I need to use the integer from AssetID in order to execute it.

Do you have to quote variables in curl?

You don’t need to pass the quotes enclosing the custom headers to curl. Also, your variables in the middle of the data argument should be quoted. First, write a function that generates the post data of your script.

Can you call subshells and reference VARs in curl?

As you can see you can call subshells and whatnot as well as reference vars in the heredoc. Happy hacking hope this helps with the ‘”‘”‘”””””'”””. A few years late but this might help someone if you are using eval or backtick substitution: