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How to print nth line after matching line?
You can try the -A option with grep, which specifies how many lines after the matching line should be printed. Couple this with sed, and you would get the required lines. Using sed, we delete the from the second line until the fourth. I’m simply adding a deletion of the appropriate lines, before printing { 3,5d ; p }.
How to print from nth column to last in Unix?
OFS : ORS)}’ input This will take n as the value of n and loop through that number through the last field NF, for each iteration it will print the current value, if that is not the last value in the line it will print OFS after it (space), if it is the last value on the line it will print ORS after it (newline).
How to print a matching line in Perl?
In Perl. the special variable $. is the current line number. So, each time I find a line matching pattern, I print it and save its line number as $c. I then print again when the current line number is 4 more than the one printed previously. You’re essentially doing a find and replace.
How does shell script print line from matched line?
When it finds a match it stores the record number ( NR) in the array nr. It also stores the 4th record from NR in the same array. This is done by the nr [NR+4]. Every record ( NR) is then checked to see if it’s present in the nr array, if so the record is printed.
How to match rows with previous rows in SQL Server?
In SQL Server versions prior to 2012, you need to perform a join using a row enumerator to match up rows with previous or next rows. In 2012 and higher, there are two functions, Lag () and Lead (), that greatly simplify the process.
How to extract all lines in a file?
I want to extract all the lines in a file containting these patterns: “#1:” and “tree length for”.
How to print a line that matches a pattern?
/pattern/s/.*/_/: if current line matches pattern, which means we should print the NEXT following line, then we need to set a indicator to tell sed to print NEXT line, so use s/.*/_/ to substitute all contents in pattern space to a _ (the second command will use it to judge if last line matched the pattern or not).
How to print all lines after a pattern?
I needed to print ALL lines after the pattern ( ok Ed, REGEX ), so I settled on this one: If pattern match, copy next line into the pattern buffer, delete a return, then quit — side effect is to print. Actually sed -n ‘/pattern/ {n;p}’ filename will fail if the pattern match continuous lines:
Can you print line that matches Regex but not the line before it?
I can get the line that matched the regex but not the line immediately before that: I created the following awk script. Prints the matching line as well as the previous 2 lines. You can make it more flexible from this idea. The awk to do the same thing is very long-winded, see Marco’s answer.