How do I print the last line?

How do I print the last line?

Use the right tool for the job. Since you want to get the last line of a file, tail is the appropriate tool for the job, especially if you have a large file….Find out the last line of a file:

1. Using sed (stream editor): sed -n ‘$p’ fileName.
2. Using tail: tail -1 fileName.
3. using awk: awk ‘END { print }’ fileName.

Which command will print the last line of a line?

Tail
Tail is a command which prints the last few number of lines (10 lines by default) of a certain file, then terminates. Example 1: By default “tail” prints the last 10 lines of a file, then exits.

How do I print the first 10 lines in Linux?

Type the following head command to display first 10 lines of a file named “bar.txt”:

1. head -10 bar.txt.
2. head -20 bar.txt.
3. sed -n 1,10p /etc/group.
4. sed -n 1,20p /etc/group.
5. awk ‘FNR <= 10’ /etc/passwd.
6. awk ‘FNR <= 20’ /etc/passwd.
7. perl -ne’1..10 and print’ /etc/passwd.
8. perl -ne’1..20 and print’ /etc/passwd.

How to print a line between two patterns?

/PAT1/ {flag=1} sets the flag when the text PAT1 is found in a line. /PAT2/ {flag=0} unsets the flag when the text PAT2 is found in a line. flag is a pattern with the default action, which is to print $0: if flag is equal 1 the line is printed.

How to print lines between two patterns in SED?

You can do what you want with sed by suppressing the normal printing of pattern space with -n. For instance to include the patterns in the result you can do: sed -n ‘/PAT1/,/PAT2/ – locate the range between PAT1 and PAT2 and suppress printing;

How to grep lines between start and end pattern?

But in the file I don’t know what is the exact occurrence (position) of end string pattern (file is having 20000 rows) How can I achieve this? grep won’t help you here. This is a job better accomplished with sed using range expressions: sed -n suppresses the automatic printing, so that lines are printed just if explicitly asked to.