How do I print the first line of a file in shell script?

How do I print the first line of a file in shell script?

To store the line itself, use the var=$(command) syntax. In this case, line=$(awk ‘NR==1 {print; exit}’ file) . With the equivalent line=$(sed -n ‘1p’ file) . will be marginally faster as read is a built-in bash command.

How do you print the number of lines in a file in Python?

Use len() to get the number of nonempty lines in the file.

1. file = open(“sample.txt”, “r”)
2. line_count = len(nonempty_lines)
3. file.
4. print(line_count)

How do you print the first N line of a file in Python?

How to print the first n lines of a file in Python

1. a_file = open(“file_name.txt”) Open “file_name.txt”
2. number_of_lines = 3.
3. for i in range(number_of_lines): Print the first number_of_lines lines of a_file.
4. line = a_file. readline()
5. print(line)

How do I count the number of lines in a file in Java?

Open the file. Read line by line, and increases count + 1 each line. Close the file. Read the count….5.2 Rerun 5-10 times the same method and get the average benchmark, here’s the result:

1. Files.
2. BufferedReader – 6-8 seconds.
3. LineNumberReader – 6-8 seconds.
4. BufferedInputStream – 4-5 seconds.

How to count the number of lines in a text file?

To get the number of lines in a text file you can use: number_of_lines = len(open(‘this_is_file.txt’).readlines())

How to print the first line of a file?

% cat foo.txt line #1 in foo line #2 in foo line #3 in foo % cat bar.txt line #1 in bar line #2 in bar line #3 in bar % for f in *.txt; do <“$f” read line; printf “$line ” >>new.txt; done % cat new.txt line #1 in bar line #1 in foo sed also allows printing of specific lines . Here I’ve combined that with find

How to get the number of lines in a file in Python?

Steps to get the line count of a large file in Python? Pass file path and access mode r to the open () function to read a file. For example, fp= open (r’File_Path’, ‘r’) to read a file. Use for loop with enumerate () function to get a line and its number.

How to print the top n lines of a file?

Here’s a general-purpose batch file to print the top n lines from a file like the GNU head utility, instead of just a single line. @echo off if [%1] == [] goto usage if [%2] == [] goto usage call :print_head %1 %2 goto :eof REM REM print_head REM Prints the first non-blank %1 lines in the file %2.