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How to specify two field separators in AWK?
How can we specify two field separators in awk command when one of them is space? I think this can be done by using an embedded if-else condition in awk, however I am not sure about the exact command. I want to print the second column ($2).
How to select text between two patterns with AWK?
A GNU* awk variant, just make PAT2 the record separator RS, PAT1 the field separator FS and print the last field NF, making sure that the output is not the result of a repetition of RS
When to use multiple delimiters in AWK stack?
Use awk -F’ [] []’ but awk -F’ [ []]’ will not work. For a field separator of any number 2 through 5 or letter a or # or a space, where the separating character must be repeated at least 2 times and not more than 6 times, for example:
How is splitting on whitespace related to AWK?
Defaults to splitting on whitespace Perl is closely related to awk, however, the @F autosplit array starts at index $F [0] while awk fields start with $1. I see many perfect answers are up on the board, but still would like to upload my piece of code too,
What’s the difference between AWK and Perl autosplit array?
Perl is closely related to awk, however, the @F autosplit array starts at index $F [0] while awk fields start with $1. I see many perfect answers are up on the board, but still would like to upload my piece of code too,
How to make AWK ignore the field delimiter inside double quotes?
Closed 6 years ago. I need to delete 2 columns in a comma seperated values file. Consider the following line in the csv file: But the embedded comma which is inside quotes is creating a problem, Following is the result I am getting: Now my question is how do I make awk ignore the “,” which are inside the double quotes?
How to ignore the field delimiter inside double?
If the current field ends with a double-quote, this then increments the field counter by 2. This is how we skip over fields 2 and 3. After we are done with the for loop, this prints a newline.