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How do I ignore white space in grep?
‘^’ and ‘$’ are regex characters. So the command grep -v will print all the lines that do not match this pattern (No characters between ^ and $). This way, empty blank lines are eliminated. egrep already do regex, and the \s is white space.
What characters need to be escaped grep?
If you include special characters in patterns typed on the command line, escape them by enclosing them in single quotation marks to prevent inadvertent misinterpretation by the shell or command interpreter. To match a character that is special to grep –E, put a backslash ( \ ) in front of the character.
How to deal with whitespace in grep super user?
The manual tells me nothing. \\s seems to work for whitespace, and \\S seems to work for non-whitespace, but it includes all whitespace characters (spaces AND tabs) and it doesn’t work if I put it in brackets, treating the backslash and the \\s as separate characters. Are you sure about that?
How to ignore the tabs or spaces and grep daemon.debug?
I want to grep daemon.debug @10.10.10.10 on all reports to make sure it is pointing to the right IP address. the problems is the space between debug and @10 are different on all the reports, some have one space some have two and some have tabs how do I ignore the tabs or spaces and grep daemon.debug @10.10.10.10
When to use s or s in grep?
Use \\s for matching any whitespace character (like space or tab). Last edited by zirias; 06-29-2010 at 02:07 PM. Reason: regex syntax Visit pixellany’s homepage!
Is there any way to get rid of leading whitespaces?
I’m greping through a large codebase, and leading whitespaces and tabulation seem to be quite annoying. Is there any way to get rid of it? grep -R “something” ./ output (run it to get the colour). Assuming you’re looking for pattern re (a basic regular expression) in one file, and you’d like to strip leading whitespace from all matching lines: