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How can I print all the lines between two lines?
Closed 5 years ago. How can I print all the lines between two lines starting with one pattern for the first line and ending with another pattern for the last line? I guess it was a mistake to mention that this document is HTML. I seem to have touched a nerve, so forget that.
How does multiple line output work in Bash?
Thus (1) preserves the shape of the input variable, whereas (2) creates a potentially very long single line of output with ‘words’ separated by single spaces (where a ‘word’ is a sequence of non-whitespace characters; there needn’t be any alphanumerics in any of the words).
How to show same number of lines before and after in grep?
If you want the same number of lines before and after you can use -C num. This will show 3 lines before and 3 lines after. -A and -B will work, as will -C n (for n lines of context), or just -n (for n lines of context… as long as n is 1 to 9).
How to print lines between two patterns, inclusive or exclusive?
{/PAT2/!p;};}’ patternTester >> sedTesterOutput; done sed solutions seems to be twice as fast as the awk solution (Mac OS). This might work for you (GNU sed) on the proviso that PAT1 and PAT2 are on separate lines: Turn off implicit printing by using the -n option and act like grep.
How to print lines between two patterns in shell?
By placing flag at the very end, it triggers the action that was set on either PAT1 or PAT2: to print on PAT1, not to print on PAT2. By placing flag at the very beginning, it triggers the action that was set previously and hence print the closing pattern but not the starting one.
How to print lines between two patterns in Perl?
For the -n option, see perldoc perlrun, which makes Perl behave like sed -n. Perl Cookbook, 6.8 for a detailed discussion of extracting a range of lines. This deletes all lines except for those between and including START and END, then the //d deletes the START and END lines since // causes sed to use the previous patterns.
Where are the pattern1 and pattern2 lines in SED?
I want to include the pattern1 and pattern2 lines in my output, but I don’t want anything after the pattern2 line. pattern2 is found in one of the lines of the section. I don’t want to stop there, but that’s easily remedied by indicating the start of the line with ^.
How to make SED quit at a pattern?
Thank you. You can make sed quit at a pattern with sed ‘/pattern/q’, so you just need your matches and then quit at the second pattern match: That way only the first block will be shown. The use of a subcommand ensures that ^pattern2 can cause sed to quit only after a match for ^pattern1.