Can a grep output be stored in an array?

Can a grep output be stored in an array?

If you need access to arbitrary elements, you can store the array first, and then retrieve the element: but this will not put each line of grep output into a separate element of an array. If you care for whole lines instead of words, you can use head and tail for this task, like so:

How to get only file names in grep?

Also you can use grep -l to get only file names in grep ‘s output (as shown in my command). Not the answer you’re looking for? Browse other questions tagged arrays bash shell or ask your own question.

How to assign the output of a command into an array?

To assign the output of a command to an array, you need to use a command substitution inside of an array assignment. For a general command command this looks like: arr= ($ (command)) In the example of the OP, this would read:

How can I use grep for multiple strings?

For example, to show the count of multiple matches in the bootstrap.log file, enter: The output prints the number of matches. This way, you can quickly determine if the number of warnings and errors increased. You can use grep to search multiple strings in a certain type of file only.

How to grep for more than two words?

To search for more than two words, keep adding them in the same manner. For example, to search for three words, add the desired string of characters followed by a backslash and pipe: Let’s see how the above grep command looks when using grep -E, egrep, and grep -e:

Can you use grep to search multiple files?

Grep for Multiple Patterns in a Specific File Type You can use grep to search multiple strings in a certain type of file only. If you want to monitor log files in one directory or if you want to search through all text files, use an asterisk and the file extension instead of a file name.

Do you need a NUL delimited output in grep?

You need a NUL-delimited output (so -print0 in find and -z in grep to process NUL-delimited records. you also forgot to pass IFS= to read. in bash, and without the lastpipe option, the last part of a pipe line runs in a subshell, so there, you’d only be updating the $arr of that subshell.

Which is the correct syntax for grep in Bash?

Or (to be compatible to even older versions of bash that didn’t have the zsh-style arr+= () syntax): with -o, grep only prints the parts of the records that match the pattern as opposed to the full record. You don’t want it here.