How to get output of grep in single line?

How to get output of grep in single line?

That is, you can change this: and add an echo command after the loop completes. The $ (…) notation sets up a “command substitution”: the command grep “$a” replaced.txt | cut -f 2 -d” ” is run in a subshell, and its output, minus any trailing newlines, is substituted into the argument-list.

How to grep two strings in one line in Python?

To get the line that contains the strings: FROM python and as build-python then use: Then the output will show only the line that contain both strings: It’s one of the quickest grepping tools, since it’s built on top of Rust’s regex engine which uses finite automata, SIMD and aggressive literal optimizations to make searching very fast.

Can you match two regexps in one line in grep?

You simply can’t do that in one call to grep, you have to either write code to escape all RE metachars before calling grep: which again are poor choices whereas with awk you simply use a string operator instead of regexp operator: Now, what if you wanted to match 2 regexps in a paragraph rather than a line? Can’t be done in grep, trivial in awk:

How to Regex match two strings in one line?

Example if the following lines are contained in a file named Dockerfile: To get the line that contains the strings: FROM python and as build-python then use: Then the output will show only the line that contain both strings:

How to get the return code of grep?

If a $ (…) command substitution is assigned to a variable, $? will get the return code from the last command in the $ (…) . And, of course, you don’t need to refer to $? explicitly; you can do things like if ! OUTPUT=$ (pfiles “$1” 2> /dev/null | grep peername) then exit fi # the rest of the script ︙

Do you quote the reference to grep in Bash?

P.S. You should always quote your shell variable references (e.g., “$1” ) unless you have a good reason not to, and you’re sure you know what you’re doing. If you need the result of grep, you can not use the -c flag as outlined in the other answer.

When to use grep with uncorrelated output?

This approach is useful in situations where the output of the command and its return code (a.k.a. exit status) are uncorrelated. But, for grep, they are highly correlated: If it produced output, it succeeded. If it didn’t produce output, it failed.

Is there a way to return 0 in grep?

Another simple way is to use grep -c. That outputs (not return as exit code), the number of lines that match the pattern, so 0 if there’s no match or 1 or more if there’s a match.

How to see output in terminal at the same time?

I have a script that outputs text to stdout. I want to see all this output in my terminal, and at the same time I want to filter some lines and save them in a file. Example: I want to see output of first command in terminal, and save the output of the second command in a file. At the same time.

Is the exit code in grep true or false?

In an if statement, a zero exit code is mapped to “true” and a non-zero exit code is mapped to false. In addition, grep has a -q argument to not output the matched text (but only return the exit status code) As a quick note, when you do something like if [ -z “$var” ]…, it turns out that [ is actually a command you’re running, just like grep.

What does the-O parameter do in grep?

The -o parameter makes grep only output the matching part of the line, which is what you want. Note that if there are several occurrences of on line, it prints the portion of the line that starts with the rightmost occurrence of it. For the leftmost occurrence: Thanks for contributing an answer to Unix & Linux Stack Exchange!

Can a grep be used to filter a file?

But it can certainly be used to filter a file out to another file, as illustrated above. The -o parameter makes grep only output the matching part of the line, which is what you want. Note that if there are several occurrences of on line, it prints the portion of the line that starts with the rightmost occurrence of it.

How to process each output line in a loop?

Process substitution is a form of redirection where the input or output of a process (some sequence of commands) appear as a temporary file. I would suggest using awk instead of grep + something else here. Real life exemple with a Symfony PHP Framework router debug command ouput, to grep all “api” related routes: