Contents
How to insert a character at a specific location using SED?
I learned this from another post: https://unix.stackexchange.com/questions/259718/sed-insert-character-at-specific-positions The following will match perform the replacement only on strings of four digits, followed by strings of two digits.
How to replace the nth occurrence of a string using SED?
Then pass it to sed and tell it to replace the nth occurrence of your string. Finally, pass the output back through tr to recreate the newlines. It can also be done with sed, WITHOUT changing the newlines first, using the following command: Thanks for contributing an answer to Stack Overflow!
How to create a single string in SED?
First replace all the newlines with a unique character that does not occur anywhere else in your file (e.g. ^) using tr. You need to do this in order to create a single string for sed. Then pass it to sed and tell it to replace the nth occurrence of your string.
How to insert a comma in a SED line?
In a general way, you can just do: sed ‘s/./&,/4’ out That will append a comma on output to the 4th character of all input lines with at least that many characters. And, if you’ll take my advice, you should generally not use the -i switch to any sed which offers one.
How to insert extra characters in a string?
I would like to insert an extra character (or a new string) at a specific location in a string. For example, I want to insert d at the fourth location in abcefg to get abcdefg. I could write a one-line simple function for this task, but I am just curious if there is an existing function for that. You can do this with regular expressions and gsub.
Do you append comma to 4th character in SED?
Otherwise, the first substitution would affect the offset for the second. You can always account for it though: That will append a comma on output to the 4th character of all input lines with at least that many characters. And, if you’ll take my advice, you should generally not use the -i switch to any sed which offers one.
How to replace a string in SED Stack Overflow?
I have a simple text file containing several lines of data where each line has got exactly 26 characters. E.g. Now, I want to replace 12th and 13th character if only these two characters are 49 with characters 58. The captured group is \\1, so you want to put the 11 (not 12) characters, then 58:
Which is the captured group in SED Stack Overflow?
The captured group is \\1, so you want to put the 11 (not 12) characters, then 58: You also need -E or -r if you don’t want to escape square and curly brackets. With your input, the command changes 49 to 58 in lines 1, 2, 4 and 5.