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How do you find the square of a submatrix?
Given an N x N matrix, find a k x k submatrix where k <= N and k >= 1, such that sum of all the elements in submatrix is maximum. The input matrix can contain zero, positive and negative numbers. For example consider below matrix, if k = 3, then output should print the sub-matrix enclosed in blue.
How many square submatrices have all ones?
Total number of squares = 10 + 4 + 1 = 15.
What does Submatrix mean?
A submatrix of A is a matrix formed by selecting from A: a subset of the rows. a subset of the columns. and forming a new matrix by using those entries, in the same relative positions, that appear in both the rows and columns of those selected.
Which is the largest square?
The Largest City Squares in the World
| Rank | Square Name | Area (Squared Meters) |
|---|---|---|
| 1 | Xinghai Square | 1,760,000 |
| 2 | Times Square | 1,440,000 |
| 3 | Merdeka Square | 1,000,000 |
| 4 | Sunflower Square | 570,000 |
How to find maximum size square sub-matrix with all 1s?
Given a binary matrix, find out the maximum size square sub-matrix with all 1s. For example, consider the below binary matrix. Recommended: Please solve it on “ PRACTICE ” first, before moving on to the solution.
How to count the number of square matrices with all 1s?
Given an N*M matrix containing only 0s and 1s, the task is to count the number of square submatrices containing all 1s. There are 10 squares of side length 1. There are 4 squares of side length 2. There is 1 square of side length 3. Total number of squares = 10 + 4 + 1 = 15.
What is the total number of squares with all 1s?
There are 10 squares of side length 1. There are 4 squares of side length 2. There is 1 square of side length 3. Total number of squares = 10 + 4 + 1 = 15. Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: This problem can be solved using Dynamic Programming .
How to find the maximum square in Stack Overflow?
To find the maximum square, we need to find the minimum extension of 1s in different directions and add 1 to it to form the length of square ending at present case.