How to make a string from a dictionary?
Keep the count of words in the map, iterate in the string and check if the word is present in the map. If present, then decrease the count of the word in the map. If it is not present, then it is not possible to make the given string from the given dictionary of words.
How to break a word in a dictionary?
Given an input string and a dictionary of words, find out if the input string can be segmented into a space-separated sequence of dictionary words. See following examples for more details.
How to check if given string of words can be formed from?
Keep the count of words in the map, iterate in the string and check if the word is present in the map. If present, then decrease the count of the word in the map. If it is not present, then it is not possible to make the given string from the given dictionary of words. Below is the implementation of above approach :
How to segment a string into a space separated sequence?
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. dict = [“leet”, “code\\. Return true because “leetcode” can be segmented as “leet code”.
How to find all words in a dictionary?
If the dictionary is long and the list of letters is short, it may be best to sort the dictionary (if it is not already), then construct all possible words by permuting the letters (removing duplicates). Then do a binary search using string comparison for each combination of letters to see if it is a word in the dictionary.
How do you sign letters in a dictionary?
“Sign” the letters available by sorting them in order; that’s O (m log m), where m is the number of letters. “Sign” each word in the dictionary by sorting the letters of the word in order; that’s O (k log k), where k is the length of the word.
How to find the indices of multiple words?
Let’s say that you would want to find the third occourance of the word, and then randomly the first, and the fifth, and the second… Then you would want to store the indices in a List, not a Stack. And why deal with multiple words at the same time?
How to generate meaningful word clouds in Python?
When the generate_from_frequencies method is used, it ignores some of the parameters including the collocations and stopword parameters. CountVectorizer processes the text, including stop words and lemmatization. If we wanted to make additional tweaks to the words, it would need to be done prior to placing them into the WordCloud object.