How do you swap two elements in a linked list?

How do you swap two elements in a linked list?

Algorithm

1. Create a class Node which has two attributes: data and next.
2. Create another class SwapNodes which has two attributes: head and tail.
3. addNode() will add a new node to the list:
4. swap() will swap the given two nodes present in the list:
5. display() will display the nodes present in the list:

How do you sort a linked list not by swapping their values?

The idea is to first search x and y in the given linked list. If any of them is not present, then return. While searching for x and y, keep track of current and previous pointers. First change next of previous pointers, then change next of current pointers.

How do you find the intersection of two linked lists?

This solution requires modifications to basic linked list data structure. Have a visited flag with each node. Traverse the first linked list and keep marking visited nodes. Now traverse the second linked list, If you see a visited node again then there is an intersection point, return the intersecting node.

How sorting is performed in linked list?

Below is a simple insertion sort algorithm for a linked list. 1) Create an empty sorted (or result) list 2) Traverse the given list, do following for every node. ……a) Insert current node in sorted way in sorted or result list. 3) Change head of given linked list to head of sorted (or result) list.

Is swap function in C++?

The function std::swap() is a built-in function in the C++ Standard Template Library (STL) which swaps the value of two variables. Parameters: The function accepts two mandatory parameters a and b which are to be swapped. Return Value: The function does not return anything, it swaps the values of the two variables.

How to swap elements of a given linked list?

For example, if the linked list is 1->2->3->4->5->6->7 then the function should change it to 2->1->4->3->6->5->7, and if the linked list is 1->2->3->4->5->6 then the function should change it to 2->1->4->3->6->5 This problem has been discussed here. The solution provided there swaps data of nodes.

How to pairwise swap adjacent nodes of a linked list?

We explicitly change pointers of first two nodes, then fix remaining nodes. The approach here is to use the double pointers so that we need not update the head pointer during swap separately. Attention reader! Don’t stop learning now.

When to change links instead of swapping data?

The solution provided there swaps data of nodes. If data contains many fields, there will be many swap operations. So changing links is a better idea in general. Following is the implementation that changes links instead of swapping data. field from the nodes. of unnecessary swap calls.

How to move two nodes ahead in a linked list?

Make ptrOne_prev .next = ptrTwo; if ptrOne_prev is not null (swapped the ptrTwo ). Make the ptrTwo as newHead (this step will happen only once). Move 2 nodes ahead for next pair wise swap. See the code for more understanding. This approach is easy compare to iterative approach. Change the links for first two nodes.