What is the sum of three multiples of 5?

What is the sum of three multiples of 5?

45
The sum of three consecutive multiples of 5 is 45.

What are multiples of 5 and 3?

This is sometimes abbreviated as “LCM.” 15 and 30 are common multiples of 3 and 5.

What is the sum of multiples of 3?

The first five multiples of 3 are 3, 6, 9, 12, and 15. Hence, the sum of first five multiples of 3 is 45.

What is the sum of first five multiples of 5?

What is the sum of the first five multiples of 5? The first five multiples of 5 are 5, 10, 15, 20, and 25. The sum of the first five multiples of 5 is 75.

What is the sum of first 7 multiples of 5?

Answer: 140 is the sum of first seven multiples of 5…..

How do you find the multiples of 5 in python?

Method 1 (Repeatedly subtract 5 from n) Run a loop and subtract 5 from n in the loop while n is greater than 0. After the loop terminates, check whether n is 0. If n becomes 0 then n is multiple of 5, otherwise not.

How to find the sum of multiples of 3 and 5?

Find the sum of all the multiples of 3 or 5 below 1000. Let’s declare a Javascript function to sum up all the numbers that are the multiples of 3 or 5. Calling this function with input 1000 gives us the answer of 233168. The runtime complexity of the above Javascript code is O (N) and the space requirement is O (1) constant.

How to do sum of multiples in JavaScript?

Since you seem to be very interested in an API where you can specify a list of divisors to check, you might like this solution. I can’t speak to it’s efficiency though.

How to find all the multiples of 3 or 5 below 1000 in Python?

You are overcomplicating things. You just need a list of numbers that are multiples of 3 or 5 which you can get easily with a list comprehension: Or even better use a generator expression instead: Or even better better (courtesy Exelian):

How to count multiples of 3 in Excel?

This is one of those programming problems where there’s a special trick that can give you a better algorithm, in this case constant-time instead of linear. If you add the multiples of 3 and the multiples of 5, you’ll count the multiples of 15 twice. So subtract those out. The answer becomes (3+6+9+…+999) + (5+10+15+…+995) – (15+30+45+…+990).