How do you sort even and odd elements of an array separately?
Algorithm:
- Initialise two index variable , left=0 and right=arr.length-1.
- Increment left variable until you get odd number.
- Decrement right variable until you get even number.
- If left < right, swap arr[left] and arr[right]
- In the end, you will see that you have even numbers on left side and odd numbers on right side.
Can you make an array with an odd number?
Odds and Evens Even numbers can be made into two-row arrays, but odd numbers cannot – there being always one item left over. The making of two rows highlights the fact that even numbers are always divisible by two.
How to arrange odd and even numbers in an array?
This is similar to an implementation of partition method of quick sort.We start from the left and keep two index one for even position and other for odd positions. Traverse these index from left. At even position there should be even number and at odd positions, there should be odd number .
Are there odd numbers at even and odd index?
Start from the left and keep two index one for even position and other for odd positions. Traverse these index from left. At even position there should be even number and at odd positions, there should be odd number. Whenever there is mismatch , we swap the values at odd and even index.
How to print array elements present at odd position?
The program was written under Code::Blocks IDE, therefore after successful build and run, this is the first snapshot of the sample run: Supply any 10 numbers or elements for the array and press ENTER key to see the value stored at odd position (odd index position): Now let’s modify the above program to allow user to decide the length of the array:
How to assign elements to odd and even positions?
If we assign the largest [n/2] elements to the even positions and the rest of the elements to the odd positions, our problem is solved. Because element at the odd position will always be less than the element at the even position as it is the maximum element and vice versa. Sort the array and assign the first [n/2] elements at even positions.