How do you find XOR of consecutive numbers?

How do you find XOR of consecutive numbers?

1- Traverse all numbers from 1 to n. 2- Do XOR of numbers one by one with result….Method 2 (Efficient method) :

1. Find the remainder of n by moduling it with 4.
2. If rem = 0, then xor will be same as n.
3. If rem = 1, then xor will be 1.
4. If rem = 2, then xor will be n+1.
5. If rem = 3 ,then xor will be 0.

How do you find the XOR of all elements in a list?

Therefore, the following steps are followed to compute the answer:

1. Create a variable to store the XOR of the array as a result.
2. For each element in the array, find the XOR of the element and the result variable using ‘^’ operator.
3. Finally, the result variable stores the XOR of all elements in the array.

What is a XOR 0?

XOR is a logical operator that works on bits. Let’s denote it by ^ . If the two bits it takes as input are the same, the result is 0 , otherwise it is 1 . This implements an exclusive or operation, i.e. exactly one argument has to be 1 for the final result to be 1 .

How do you make XOR of K consecutive elements zero?

To remove the contribution of the first element, we XOR with it, which means the only option to make the next window XOR to zero is to XOR with the element we just removed. This means the optimal first k elements must continue to repeat throughout.

How to calculate xor of consecutive values in Java?

Note that in examples below ^ does not mean power but integer xor (like in C or Java language) So, xored (0) = 0, xored (1) = 0 ^ 1, xored (2) = 0 ^ 1 ^ 2, xored (3) = 0 ^ 1 ^ 2 ^ 3, etc… First, I created a naive implementation that that loops through the values and xors them together.

How to calculate xor of numbers from 1 to N?

1- Traverse all numbers from 1 to n. 2- Do XOR of numbers one by one with result. 3- At the end, return result. 1- Find the remainder of n by moduling it with 4. 2- If rem = 0, then xor will be same as n. 3- If rem = 1, then xor will be 1. 4- If rem = 2, then xor will be n+1. 5- If rem = 3 ,then xor will be 0.

Why is xor of consecutive integers an interesting property?

XORing consecutive integers has an interesting property. Does anyone know why? (1 answer) Closed 5 years ago. I was trying to calculate integer xor of 0..n. I named the function xored (n). Note that in examples below ^ does not mean power but integer xor (like in C or Java language)

How to count the number of subsets with a particular XOR value?

Counting the number of subsets with XOR value k: Since dp [i] [j] is the number of subsets having j as XOR value from the subsets of arr [0..i-1], then the number of subsets from set arr [0..n] having XOR value as K will be dp [n] [K] This article is contributed by Pranay Pandey.