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How is the concat method used in IEnumerable?
The Concat method will return an object which implements IEnumerable by returning an object (call it Cat) whose enumerator will attempt to use the two passed-in enumerable items (call them A and B) in sequence.
How to use Concat to concatenate two sequences?
The sequence to concatenate to the first sequence. An IEnumerable that contains the concatenated elements of the two input sequences. first or second is null. The following code example demonstrates how to use Concat (IEnumerable , IEnumerable ) to concatenate two sequences.
What is the type of an IEnumerable < T >?
The type of the elements of the input sequences. The first sequence to concatenate. The sequence to concatenate to the first sequence. An IEnumerable that contains the concatenated elements of the two input sequences. first or second is null.
Can a LINQ object be an enumerable object?
Yes, LINQ to Objects supports this with Enumerable.Concat: NB: Should first or second be null you would receive a ArgumentNullException. To avoid this & treat nulls as you would an empty set, use the null coalescing operator like so: var together = (first ??
What happens when you merge two IEnumerable < T > S?
I have two IEnumerable<T>s. One gets filled with the fallback ellements. This one will always contain the most elements. The other one will get filled depending on some parameters and will Stack Overflow About Products For Teams Stack OverflowPublic questions & answers
Can a string be added to an IEnumerable?
Adding IEnumerable items to IEnumerable , You can’t add anything to an existing IEnumerable -> it is a read-only-collection! – bash.d Aug 20 ’13 at 8:23. you can use the extension method Concat to concatenate two ienumerable – Fabio Marcolini Aug 20 ’13 at 8:23.
How to add an item to an IEnumerable [ ] collection?
How can I add an item to a IEnumerable collection?, What you can do is use the Add extension method to create a new IEnumerable with the added value. var items = new string [] {“foo”}; var temp = items; items = items.