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What is collector base voltage?
The Collector−Emitter Voltage, VCEO, spec states the maximum voltage that can be applied from the collector to emitter is 50 V. There are two maximum ratings for the input voltage, forward and reverse. The input voltage is defined as the voltage applied from the base and the emitter.
How is collector base voltage calculated?
This can be done using the formula: Vcc = Vrc + Vrb + Vbe + (Ic + Ib)Rc + IbRb + Vbe, where “Vrc” is the voltage across the collector resistor; “Vrb” is the voltage across the base resistor (connected across the base) and the junction between the collector resistor and the transistor collector; and “Vbe” is the voltage …
What is the supply voltage between the base and the collector?
The supply voltage between the collector and the base is denoted by VCB. The collector is biased to a higher positive level than the base to keep the collector-base junction reverse biased. The pnp transistor is formed by sandwiching the single n-type semiconductor layer between the two p-type semiconductor layers.
Do you need resistor between base and collector?
You need a resistor between the base and the voltage supply (or perhaps between the emitter and ground) to dissipate the 4.3 volts. Without this, younhave something much like a short circuit, and the transistor might not survive. Thanks for contributing an answer to Electrical Engineering Stack Exchange! Please be sure to answer the question.
What is the voltage drop between collector and emitter?
The collector voltage, ( Vc ) must be greater and positive with respect to the emitter voltage, ( Ve ) to allow current to flow through the transistor between the collector-emitter junctions. Also, there is a voltage drop between the Base and the Emitter terminal of about 0.7V…
What is the base voltage of a NPN transistor?
I’ve read that with an NPN transistor, there is a voltage drop of about 0.6v between the base and the emitter. So you need to have about 0.7v on the base to switch it on (circuit 1) But what happens when you have say 5v on the base? (circuit 2) Where does that extra 4.3v go? what is it being dropped across?