How do you find duplicate numbers in an integer array?

How do you find duplicate numbers in an integer array?

Algorithm

1. Declare and initialize an array.
2. Duplicate elements can be found using two loops. The outer loop will iterate through the array from 0 to length of the array. The outer loop will select an element.
3. If a match is found which means the duplicate element is found then, display the element.

How do you find duplicate numbers in an array in C++?

1. using namespace std; // Function to find a duplicate element in a limited range array.
2. int duplicate = -1; // do for each array element.
3. // get the value of the current element. int val = abs(arr[i]);
4. if (arr[val-1] >= 0) {
5. // if the element is already negative, it is repeated.
6. }
7. // make negative elements positive.
8. }

Which data structure can have duplicate keys?

Google Guava project One of these data structures is called Multimap and it allows us to store duplicate keys in a more elegant fashion.

How to find duplicates in an array of integers?

Given an array of n + 1 integers between 1 and n, find one of the duplicates. If there are multiple possible answers, return one of the duplicates. If there is no duplicate, return -1. Example: Input: [1, 2, 2, 3]

Can you solve the problem without modifying the array NUMS?

You must solve the problem without modifying the array nums and uses only constant extra space. All the integers in nums appear only once except for precisely one integer which appears two or more times.

How to find duplicate element in linked list?

The duplicate element is (X ^ Y). The above problem can be solved by the cycle finding algorithm in Linked List using two pointers slow and fast, the slow pointer moves by one step and fast move by two steps in every iteration. Initialize two pointers slow and fast as nums [0].