How many minimum number of transistors both p and n are required to construct a CMOS and gate?

How many minimum number of transistors both p and n are required to construct a CMOS and gate?

Explanation: CMOS is made up of NMOS and PMOS transistors. A NOT gate requires 2 transistors, 1 NMOS and 1 PMOS. A NAND gate requires 4, a 2 input AND requires 6.

How many MOSFETs are required for a 2 input CMOS and gate?

A CMOS NOR gate circuit uses four MOSFETs just like the NAND gate, except that its transistors are differently arranged.

Which is not part of emitter coupled logic?

Which is not part of emitter-coupled logic (ECL)?…Discussion :: Integrated Circuit Technologies – General Questions (Q. No. 25)

[A]. Differential amplifier
[B]. Bias circuit
[C]. Emitter-follower circuit
[D]. Totem-pole circuit

Which of the following logic families has the shortest propagation delay?

Which of the following logic families has the shortest propagation delay? Explanation: AS-TTL (Advanced Schottky) has a maximum clock frequency that is 105 MHz. So, the propagation delay will be given by 1/105 sec which is the lowest one. It is followed by S-TTL and HCMOS in terms of increasing propagation delay.

How does a NAND gate behave like a CMOS circuit?

The above drawn circuit is a 2-input CMOS NAND gate. Now let’s understand how this circuit will behave like a NAND gate. The circuit output should follow the same pattern as in the truth table for different input combinations. As V A and V B both are low, both the pMOS will be ON and both the nMOS will be OFF.

Which is dual of PDN and NAND gate?

B is dual of the PDN which consists of parallel combination of two PMOS transistors as shown in Figure. Construction of CMOS AND gate : When we combine both the PDN and PUN the circuit will produce NAND gate i.e. –––––––A ?

What is the V out of NAND NOR gate?

In all the 4 cases we have observed that V out is following the expected value as in 2 input NOR gate truth table. In case of NAND gate, 3 pMOS will be connected in parallel and 3 nMOS will be connected in series, and other way around in case of 3 input NOR gate.

What happens when both NMOS and PMOs are on?

As V A and V B both are low, both the pMOS will be ON and both the nMOS will be OFF. So the output V out will get two paths through two ON pMOS to get connected with V dd. The output will be charged to the V dd level. The output line will not get any path to the GND as both the nMOS are off.