Which of the following are true when the npn transistor is saturated?

Which of the following are true when the npn transistor is saturated?

Which of the following is true for a npn transistor in the saturation region? Explanation: The commonly used npn transistors have a potential difference of around 0.5V between he collector and the base. Explanation: The value of Vcb is -0.5V for a pnp transistor and 0.5V for an npn transistor.

When operated in cutoff and saturation the transistor acts as?

The four transistor operation modes are: Saturation — The transistor acts like a short circuit. Current freely flows from collector to emitter. Cut-off — The transistor acts like an open circuit.

Is the device which acts like an npn and a PNP transistor connected base to base and emitter to collector?

Right Answer is: D An SCR – Silicon controlled rectifier is 4 layered solid-state current controlling device. The operation of SCR is similar to a PNP and NPN transistors connected base to collector and emitter to base.

What’s the difference between a transistor and a NPN switch?

The equations for calculating the Base resistance, Collector current and voltages are exactly the same as for the previous NPN transistor switch. The difference this time is that we are switching power with a PNP transistor (sourcing current) instead of switching ground with an NPN transistor (sinking current).

What is the saturation region of a PNP transistor?

Therefore the transistor is switched “Fully-ON”. Then we can define the “saturation region” or “ON mode” when using a bipolar transistor as a switch as being, both junctions forward biased, VB > 0.7v and IC = Maximum. For a PNP transistor, the Emitter potential must be positive with respect to the Base.

How does saturate depend on the type of transistor?

How much current will depend on the type of transistor. ‘saturation’ has to do with how many of the charge carriers in the base region can make it into the collector region. Some will come from the base terminal, but many more will come into the base region from the emitter region.

Why does a BJT transistor have to be saturated?

BJT transistor will be saturated the moment the Ic will not follow the linear relation of: I c = H F E ∗ I b. Thus all we have to do is to limit the Ic from reaching this value. Since I b is determined by the value of the resistor connected to the base and the driving voltage on its other end, it is easy to force I b to any value.