What is the voltage across inductor at t 0?

What is the voltage across inductor at t 0?

As soon as the switch is closes at t=0+, the inductor acts as an open circuit, hence the current in the circuit is zero. Since the current in the circuit is zero, there is no voltage drop across the resistor and the voltage across the inductor is equal to the supply voltage, which is equal to 60V.

What is the potential difference across the inductor at t 0?

E.g. What is the potential difference across the inductor at t = 0? through the circuit is 0.

Can the voltage across an inductor make a step jump?

“the voltage across the inductor will immediately jump to battery voltage (acting as though it were an open-circuit) and decay down to zero over time (eventually acting as though it were a short-circuit).”

How do you find the potential difference across the inductor?

Z=√R²+(Xl-Xc) Where: Z is the impedance, Xl is the inductive reactance, and Xc is the capacitive reactance.

When does the voltage across the inductor jump?

At t=0 the voltage across the Inductor will immediately jump to battery voltage. Why? While reading transients i come to read…… “the voltage across the inductor will immediately jump to battery voltage (acting as though it were an open-circuit) and decay down to zero over time (eventually acting as though it were a short-circuit).”

When is the current zero in the inductor?

But then at t= 0 they claim that the current is zero in the inductor. So when the current is zero in the Inductor then how a magnetic field can be built to induce opposite voltage across the inductor.

What happens to the voltage when the switch is closed?

Extra credit: if the switch is closed for a long time, the voltage accross the inductor is 0. Hence no current is flowing through the 3kOhm resistor, and the current flowing through the inductor is 5/2k = 2.5mA. The switch is opened: the current flowing through the inductor is still 2.5mA.