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How do you find the repeating sequence of characters in an array?
14 Answers
- get the first character of the array (for your last example, that would be C )
- get the index of the next appearance of that character in the array (e.g. 9)
- if it is found, search for the next appearance of the substring between the two appearances of the character (in this case CARPENTER )
How do you find duplicate characters in a string C++?
Program explanation
- Initialize a string of length 80.
- Take the input string value from the user.
- Use nested for loop to traverse through the string.
- Use a conditional statement (if) to perform the function.
- Print the duplicate values each time any duplicate character is detected.
How to find longest sequence of same characters in string?
Well, the solution a bit depends on the additional requirements. Here is the code which returns the FIRST longest sequence of a repeated character int the given string, meaning if you have a second sequence with the same length you never get it out : (. But still, this is a simple and clear solution here, so good news – it works!
How to find the length of the longest repeating subsequence?
To find the length of the Longest Repeating Subsequence dynamic programming Top-down Approach: Take the input string. Perform the Longest common subsequence where s1 [i]==s1 [j] and i!=j. Return the length. # same index are not considered. Attention reader!
How to count the longest repeat in a string?
What’s the easiest way to count the longest consecutive repeat of a certain character in a string? For example, the longest consecutive repeat of “b” in the following string: would be 6, since other consecutive repeats are shorter (3 and 2, respectively.) How can I do this in Python?
Which is the longest sequence of non repeating letters?
The test case you’re missing is longer text with non-repeating letters, for example: abcdefghijkl. And it’s easy to fix that: just add these lines before the return statement: The biggest clue for figuring out this problem was around these lines: