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How to count neighbors in game of life?
My method for counting neighbors in my soon-to-be Game of Life implementation is very repetitive and I was wondering if this could be done more elegantly: Because officially the board should be infinite, I don’t need out-of-bounds checks in this code – I assume the board is infinite here -, but my Board implementation secretly looks like this:
What are the neighbors of a cell in Conways game of life?
Neighbors of a cell are cells that touch that cell, either horizontal, vertical, or diagonal from that cell. The initial pattern is the first generation. The second generation evolves from applying the rules simultaneously to every cell on the game board, i.e. births and deaths happen simultaneously.
Can a game of life be adapted to more than two players?
This variant of life can well be adapted to multiple players. However, with more than two players, it is possible that a newborn cell will have three neighbors belonging to three separate players. In that case, the newborn cell is neutral, and does not belong to anyone.
How is the game of life played in a cell?
The Game of Life (an example of a cellular automaton) is played on an infinite two-dimensional rectangular grid of cells. Each cell can be either alive or dead. The status of each cell changes each turn of the game (also called a generation) depending on the statuses of that cell’s 8 neighbors.
How to optimize the game of life stack?
There are some super-fast implementations that (from memory) represent cells of 8 or more adjacent squares as bit patterns and use that as an index into a large array of precalculated values to determine in a single machine instruction if a cell is live or dead. You should look into Hashlife, the ultimate optimization.
How can you count the number of neighbors in a cell?
You can also count neighbors by having your cells contain their number of neighbors all the time. When a cell becomes “alive” it updates all surrounding cells by one and when one “dies” it decrements all surrounding cells.
How to speed up the game of life algorithm?
As mentioned in Arbash’s Black Book, one of the most simple and straight forward ways to get a huge speedup is to keep a change list. Instead of iterating through the entire cell grid each time, keep a copy of all the cells that you change. This will narrow down the work you have to do on each iteration.
How to check the neighbors of a point?
All points on the edge would now also have 8 neighbors, but those neighbors would cross over. For example, Point (0, 0) ‘s neighbors would include Point (0, 1), Point (n – 1, n – 1), Point (0, n – 1), etc. The answer by rolfl is great, I will just add that what you have here is a nice use-case for enums.
What’s the best way to check for Neighbours in Java?
And if your board would be infinite, the method would just always return 8 anyways. Make your board slightly bigger so it gets a single tile unused border. Never examine cells on the border. This way you can omit the tests as you never land out of bounds. This makes the code a bit shorter and faster.