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What is depth of a node in binary tree?
The depth of a node in a binary tree is the length of the path from the root of the tree to that node. That is, the root has depth 0, its children have depth 1, its grandchildren have depth 2, and so on. In a balanced tree, all the leaves in the tree are about the same depth.
What is left node in binary tree?
A binary tree is made of nodes, where each node contains a “left” reference, a “right” reference, and a data element. The topmost node in the tree is called the root. On the other hand, each node can be connected to arbitrary number of nodes, called children. Nodes with no children are called leaves, or external nodes.
Which is the left most leaf node?
The deepest left leaf node is the node with value 9. Recommended: Please try your approach on {IDE} first, before moving on to the solution. The idea is to recursively traverse the given binary tree and while traversing, maintain “level” which will store the current node’s level in the tree.
What is leaf node in DS?
Child − The node below a given node connected by its edge downward is called its child node. Leaf − The node which does not have any child node is called the leaf node. Subtree − Subtree represents the descendants of a node. Visiting − Visiting refers to checking the value of a node when control is on the node.
How to find deepest left leaf in binary tree?
Begin. function deepestLLeafutil () find the deepest left leaf in a given binary tree: lvel is level of current node. maxlvel is pointer to the deepest left leaf node found so far isLeft Indicates that this node is left child of its parent resPtr is Pointer to the result If root is equal to Null then Return.
How to update the current leaf node in a binary tree?
If the current node is left and is leaf node, then update the result node with current node. Call the recursive function on left sub tree. Call the recursive function on right sub tree.
How to find the maximum depth of a node?
If current node is not leaf, then recursively find maximum depth in left and right subtrees, and return maximum of the two depths. Thanks to Coder011 for suggesting this approach. Time Complexity: The function does a simple traversal of the tree, so the complexity is O (n).