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Can a single quote occur between two quotes in Bash?
A single quote may not occur between single quotes, even when preceded by a backslash. so bash won’t understand: however, you can do this if you surround with double quotes:
How can I work with binary in Bash, to copy bytes verbatim?
In any case, command arguments and environment variables cannot contain those bytes as they are NUL delimited strings passed to the execve system call. strips all the trailing newline characters from the output of cmd. So, if that binary output ends in 0xa bytes, it will be mangled when stored in $var.
How to prevent arbitrary command execution in Bash?
The input sanitisation above relies on the fact that single quoted strings are treated as literals, that is, they are not expanded, and escape sequences are not processed. To prevent arbitrary command execution we need to prevent the single quoted string being terminated, this can be done by removing any single quotes from the input.
How to create variable with multiple ARGs in Bash?
I generate a bash variable containing all my args and those args contain spaces. When I launch a command with those args – eg. ls $args – quotes are not correctly interpreted. Here is an example – also creating and erasing needed files.
How to insert quotes in a bash argument?
You can also insert literal tabs and newlines using Ctrl – V Tab and Ctrl – V Ctrl – J within double or single quotes instead of using escapes within $’…’.
When to use single quotes in a shell?
As you can verify, each of the above lines is a single word to the shell. Quotes (single or double quotes, depending on the situation) don’t isolate words. They are only used to disable interpretation of various special characters, like whitespace, $, ; For a good tutorial on quoting see Mark Reed’s answer.
How to keep quotes in command line arguments?
Quotes are interpreted by bash and are not stored in command line arguments or variable values. If you want to use quoted arguments, you have to quote them each time you use them: As Gary S. Weaver shown in his source code tips, the trick is to call bash with parameter ‘-c’ and then quote the next.