Can we have a non recursive algorithm for inorder traversal of a binary tree that uses no stack?
Using Morris Traversal, we can traverse the tree without using stack and recursion. In this traversal, we first create links to Inorder successor and print the data using these links, and finally revert the changes to restore original tree. …
Which method of Traverse does not use stack?
Morris (InOrder) traversal is a tree traversal algorithm that does not employ the use of recursion or a stack.
How do you inorder the traversal of a tree?
You start traversal from the root≤ then go to the left node, and then again go to the left node until you reach a leaf node. At that point in time, you print the value of the node or mark it visited and moves to the right subtree. Continuing the same algorithm until all nodes of the binary tree are visited.
In which tree do we avoid the recursive method of traversing a tree?
A Threaded Binary Tree is a binary tree in which every node that does not have a right child has a THREAD in actual sense a link to its INORDER successor. By doing this threading we avoid the recursive method of traversing a Tree which makes use of stacks and consumes a lot of memory and time.
How to inorder tree traversal without recursion?
1) Create an empty stack S. 2) Initialize current node as root 3) Push the current node to S and set current = current->left until current is NULL 4) If current is NULL and stack is not empty then a) Pop the top item from stack. b) Print the popped item, set current = popped_item->right c) Go to step 3.
How is inorder traversal different from stack based traversal?
Unlike Stack based traversal, no extra space is required for this traversal. Time Complexity : O (n) If we take a closer look, we can notice that every edge of the tree is traversed at most two times. And in the worst case, the same number of extra edges (as input tree) are created and removed.
Is there an algorithm for traversing a binary tree?
Below is an algorithm for traversing binary tree using stack. See this for step wise step execution of the algorithm. 1) Create an empty stack S. 2) Initialize current node as root 3) Push the current node to S and set current = current->left until current is NULL 4) If current is NULL and stack is not empty then a) Pop the top item from stack.
How to do in order traversal of a BST without recursion?
How to do in-order traversal of a BST without recursion or stack but using parent pointers? Is it possible to do an iterative in-order-traversal on a BST whose node has a parent pointer (the parent of the root is null) without using a visited flag or a stack?