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Can you partition a chain of linked nodes?
Given a linked list and a value x, partition it such that all nodes less than x come first, then all nodes with a value equal to x, and finally nodes with a value greater than or equal to x. The original relative order of the nodes in each of the three partitions should be preserved. The partition must work in place.
How do you split a linked list?
Given a list, split it into two sublists – one for the front half and one for the back half. If the total number of elements is odd, the extra element should go in the front list. For example, list {2, 3, 5, 7, 11} should yield the two lists {2, 3, 5} and {7, 11} .
Can a linked list be circular?
Circular linked list is a linked list where all nodes are connected to form a circle. There is no NULL at the end. A circular linked list can be a singly circular linked list or doubly circular linked list. We can maintain a pointer to the last inserted node and front can always be obtained as next of last.
What is the difference between circular linked list and simple linked list?
The only difference between the singly linked list and a circular linked list is that the last node does not point to any node in a singly linked list, so its link part contains a NULL value. The circular linked list has no starting and ending node. We can traverse in any direction, i.e., either backward or forward.
How to partition a linked list around a value?
Given a linked list and a value x, partition a linked list around a value x, such that all nodes less than x come before all nodes greater than or equal to x. If x is contained within the list the values of x only need to be after the elements less than x (see below).
Where does the partition X go in a list?
If x is contained within the list the values of x only need to be after the elements less than x (see below). The partition element x can appear anywhere in the “right partition”; it does not need to appear between the left and right partitions.
How do you rearrange elements in a list?
If we don’t care about making the elements of the list “stable” then we can instead rearrange the elements by growing the list at the head and tail. In this approach, we start a “new” list (using the existing nodes). Elements bigger than the pivot element are put at the tail and elements smaller are put at the head.