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Can you sort a list based on another list?
Sorting a list based on another list sorts the elements of the first list by the value of the element in the same position in the second list. For example, sorting [“a”, “b”, “c”] based on [2, 3, 1] results in [“c”, “a”, “b”] .
How do I sort two lists based on one in Python?
How to sort two lists together in Python
- list1 = [“c”, “b”, “d”, “a”]
- list2 = [2, 3, 1, 4]
- zipped_lists = zip(list1, list2)
- sorted_pairs = sorted(zipped_lists)
- tuples = zip(*sorted_pairs)
- list1, list2 = [ list(tuple) for tuple in tuples]
- print(list1)
- print(list2)
Which function sorts a list and return another list?
correct Answer is sort().
What is a custom sort?
Doing a custom sort allows you to specify the order in which your list will be sorted in – like if you want to sort in a non alphabetical order. You may want to do a custom sort to sort items in an order that is not alphabetical or numerical.
How do you sort and compare two lists in Python?
How to compare two lists in Python?
- Using list. sort() and == operator. The list.
- Using collections. Counter() This method tests for the equality of the lists by comparing frequency of each element in first list with the second list.
- Using == operator. This is a modification of the first method.
When to use merge sort for linked lists?
Merge sort is often preferred for sorting a linked list. The slow random-access performance of a linked list makes some other algorithms (such as quicksort) perform poorly, and others (such as heapsort) completely impossible. Let the head by the first node of the linked list be sorted and headRef be the pointer to head.
How to sort one list based on another?
Although I think it’s slow — O (n*m) where n and m are the lengths of Input and Ref. @rusu_ro1’s solution uses a similar method but seems to be O (n+m). Not the answer you’re looking for? Browse other questions tagged python algorithm sorting or ask your own question.
Which is the best algorithm for sorting linked lists?
Merge Sort for Linked Lists. Merge sort is often preferred for sorting a linked list. The slow random-access performance of a linked list makes some other algorithms (such as quicksort) perform poorly, and others (such as heapsort) completely impossible.
How to merge a linked list into two halves?
MergeSort (headRef) 1) If the head is NULL or there is only one element in the Linked List then return. 2) Else divide the linked list into two halves. FrontBackSplit (head, &a, &b); /* a and b are two halves */ 3) Sort the two halves a and b.