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Can you use AWK to delimit tabs instead of spaces?
You can certainly do that with awk, too: If fields are separated by tabs and your concern is that some fields contain spaces, there is no problem here, just: (cut defaults to tab delimited fields.) Judging by the format of your input file, you can get away with delimiting on – instead of spaces:
How to use AWK on a DOS file?
The file that you run the script on has DOS line-endings. It may be that it was created on a Windows machine. Use dos2unix to convert it to a Unix text file. Then use input-unix.txt with your otherwise correct awk code. This takes the carriage-return at the end of the line into account.
How to create a variable in an AWK script?
Creating a variable with -v avoids the ugliness of trying to expand shell variables within an awk script. There are a few problems with the current code you’ve shown. The first is that your awk script is single quoted (good), which stops $threshold from expanding, and so the value is never inserted in your script.
Why is print not necessary in AWK script?
The first is that your awk script is single quoted (good), which stops $threshold from expanding, and so the value is never inserted in your script. Second, your condition belongs outside the curly braces, which would make it: This works, but the `print is not necessary (it’s the default action), which is why I shortened it to
How to use AWK to print lines where a field matches?
I need awk to print all lines in which $2 is LINUX. See awk by Example for a good intro to awk. See sed by Example for a good intro to sed. The default action of awk when in a True condition is to print the current line.
How to remove a specific character using awk or SED?
I’d like to know how to remove unwanted characters with awk or sed. s/X/Y/ replaces X with Y. g means all occurrences should be replaced, not just the first one. I can’t verify it for you because I don’t know your exact input, but the following works: See also this question on removing single quotes.
Do you need awk for read in Bash?
You don’t need awk for that. Using read in Bash shell should be enough, e.g. Then, supposing you name the script as co, say, do something like this to get the sizes of files (the example assumes you’re using Linux, but the script itself is OS-independent) :- Highly active question.
How to get the second column from command output?
The first column is always a number,My purpose is to get the second column only, like: 20.00 20.00 23.75 23.75 27.52 27.52 31.30 31.30 . . to accomplish this.but,the output is messed up: (only one value 20.00) 20.00 So,How do I get the second column’s value? (in my case I have 405 rows corresponding 405 values with 1 column)
Why is the second column of the output messed up?
But the question is, some values in the second column contain space (s), which happens to be the default delimiter for awk to separate the fields. Therefore, the output is messed up: