Can you use regex with ls?
Bash, and thus ls , does not support regular expressions here. What it supports is filename expressions (Globbing), a form of wildcards. Regular expressions are a lot more powerful than that. Find is recursive by default, but ls is not.
How do you match any string from a list of strings in regular expressions in Python?
- Join the array elements with | as glue, will form string as fun|dum|sun|gum which can be used in regex.
- re.search(‘|’.join(string_lst), input_string)
- any(z in string_list for z in re.findall(r”[‘\w]+”, ‘This is just for fun’))
- Do you care which of the strings is found, or just that any of them are found?
How to use regular expression with LS Stack Overflow?
I am trying to print all files which contains an extension (I know I could have used ls *.*, but I wanted to try using ER). When I run that code I get this error: ls: .+..+: No such file or directory. You are confusing regular expression with shell globbing.
Can a regular expression be used in Bash?
The question asked for regular expressions. Bash, and thus ls, does not support regular expressions here. What it supports is filename expressions ( Globbing ), a form of wildcards. Regular expressions are a lot more powerful than that. Find is recursive by default, but ls is not.
When to use regular expression instead of shell globbing?
When I run that code I get this error: ls: .+..+: No such file or directory. You are confusing regular expression with shell globbing. If you want to use regular expression to match file names you could do:
Can you use regular expression to match file names?
If you want to use regular expression to match file names you could do: You don’t say what shell you are using, but they generally don’t support regular expressions that way, although there are common *nix CLI tools ( grep, sed, etc) that do.