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How can I have a newline in a string in SH?
The only simple alternative is to actually type a new line in the variable: Yes, that means writing Enter where needed in the code. There are several equivalents to a new line character. ### A common way to represent a new line character. \\012 ### Octal value of a new line character. \ ### Hexadecimal value of a new line character.
How to comment a line matching a specific string?
Assuming the BBB is at the beginning of a line, I ended up using an even simpler expression: One more note for the future me. Do not overlook the -i. Because this won’t work: sed -e “…” same_file > same_file. This doesn’t work for me with the keyword *.sudo, no comments at all…
How to search and extract string from command output?
The -P option requires GNU grep. Thus, it will not work with busybox’s builtin grep, nor with the default grep on BSD/Mac OSX systems. /text4:/ selects lines that contain text4:. sub (/.*text4:/, “”) tells awk to remove all text from the beginning of the line to the last occurrence of text4: on the line. print tells awk to print those lines.
How to comment a string in regex SED?
If the pattern you’re searching for does not include a “#” it will add it to the beginning of the line, and it will also add a trailing space. Another solution with the & special character which references the whole matched portion of the pattern space.
Why are I trying to detect newlines instead of newlines?
And a string like this fail: These are the output of a sed command, namely sed ‘1d;$d’. Not sure if that matters. The reason why I am trying to detect newlines rather than ” ——-” is for defense against changes in the formatting of the file I’m parsing.
How to compare a string to a csh string?
It should work. You need to show the values of $pattern by running: echo “$pattern”. However you need to space out the if-statement components. if ( “$pattern” =~ *.gif ) then echo “pattern matches…” else echo “no match” endif Thanks for contributing an answer to Unix & Linux Stack Exchange!
How to tell if a string contains another string?
Or there’s ‘expr’: If you want a ksh only method that is as fast as “test”, you can do something like: It works by deleting the needle in the haystack and then comparing the string length of old and new haystacks. See the manpage for the ‘test’ program.