How can you tell if two strings are divisible?

How can you tell if two strings are divisible?

A string s divisible by string t if string t can be concatenated some number of times to obtain the string s. If s is divisible, find the smallest string u such that it can be concatenated some number of times to obtain both s and t. If it is not divisible, set the return value to -1.

How do you know if a string is divisible by 3?

A number is divisible by 3 if sum of its digits is divisible by 3. Illustration: For example n = 1332 Sum of digits = 1 + 3 + 3 + 2 = 9 Since sum is divisible by 3, answer is Yes.

How do you find the smallest divisor of a string?

The simplest way to find the smallest divisor of t is to check all the factors of its length to see if the prefix of that length divides t. This will tell you all the suffixes of t that are also prefixes of t. If the length of the remainder divides the length of t, then the remainder divides t.

How do you check if a string is a subsequence of another Java?

Check if one string is a subsequence of another string.

1. Given strings, A and B.
2. Check if any of the string is null, return false.
3. Compare the lengths of both the strings.
4. Now have two strings, longer and shorter.
5. Initialize the starting index for the shorter string as j = 0.

How do you know if a binary number is divisible by a power of 2?

Efficient Approach : In the binary string, check for last k bits. If the all the last k bits are 0, then the binary number is evenly divisible by 2k else it is not evenly divisible.

How do you know if a number is divisible by 4 in binary?

We have to find out which of the given binary numbers are divisible by ‘4’ . For this, we divide each of the given numbers by 4 and the number whose remainder is zero will be the one which is divisible by 4. From the above calculations, it is clear that ‘100101100’ is the only binary number which is divisible by 4.

How do you find the GCD?

The steps to calculate the GCD of (a, b) using the LCM method is:

1. Step 1: Find the product of a and b.
2. Step 2: Find the least common multiple (LCM) of a and b.
3. Step 3: Divide the values obtained in Step 1 and Step 2.
4. Step 4: The obtained value after division is the greatest common divisor of (a, b).

How do you write a GCD function in C++?

C++ code

1. #include
2. using namespace std;
3. int gcd(int a, int b) // The function runs recursive in nature to return GCD.
4. {
5. if (a == 0) // If a becomes zero.
6. return b; // b is the GCD.
7. if (b == 0)// If b becomes zero.
8. return a;// a is the GCD.

How do you check if a string is subsequence of another string in C++?

Program to check whether a string is subsequence of other in C++

1. if s is same as t, then − return true.
2. n := size of s, m := size of t.
3. j := 0.
4. for initialize i := 0, when i < n, update (increase i by 1), do − if t[j] is same as s[i], then − (increase j by 1) if j is same as size of t, then − return true.
5. return false.

How to calculate the divisibility of a string?

String s divisible by string tif string t can be concatenated some number of times to obtain the string s. o If sis divisible, find the smallest string, u, such that it can be concatenated some Question:5. Divisibility of Strings Given two strings, s and t, create a function that operates per the following rules: 1.

How to check if str sub strings are divisible by K?

Approach: Initialize count = 0. Take all the sub-strings of str and check whether they are divisible by K or not. If yes then update count = count + 1. Print the count in the end. Below is the implementation of the above approach:

How to count the number of sub strings in STR?

The task is to count the number of sub-strings of str that are divisible by K. Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: Initialize count = 0. Take all the sub-strings of str and check whether they are divisible by K or not.

How to calculate the size of two strings?

Initialize two strings S1 and T1. Concatenate the string, S1 with string, S, (L/N) number of times. Concatenate the string, T1 with string, T, (L/M) number of times. If the strings S1 and T1 are equal, then print S1 as the result.