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How do I find the closest divisible number?
We have to find the number closest to n and divide by m. If there are more than one such number, then show the number which has maximum absolute value. If n is completely divisible by m, then return n. So if n = 13, m = 4, then output is 12.
How do I find the nearest multiple of a number?
If you can round down (floor) to the nearest multiple, just add multiple/2 to the input and now you have a round function. If you want it to round up in the odd cases, add ceil(multiple/2) instead.
What is the largest 5 digit number divisible by 99?
99990 is the largest 5 digit multiple of 99.
Which multiple of 2 is closest to 5?
(ii) Multiples of 2 are: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, ………… etc. Multiples of 5 are: 5, 10, 15, 20, 25, ………… etc. Therefore, common multiples of 2 and 5 = 10, 20, ………..etc. [It can easily be seen that each of the common multiples 10, 20, etc., is exactly divisible by both 2 and 5].
How to get the closest number from a list?
Iterate over the list and compare the current closest number with abs (currentNumber – myNumber): def takeClosest (myList, myNumber): closest = myList [0] for i in range (1, len (myList)): if abs (i – myNumber) < closest: closest = i return closest. Share.
How to find the closest number to a number in Python?
6. def closest (list, Number): aux = [] for valor in list: aux.append (abs (Number-valor)) return aux.index (min (aux)) This code will give you the index of the closest number of Number in the list.
How to return the closest number to myNumber?
Returns closest value to myNumber. If two numbers are equally close, return the smallest number. “”” pos = bisect_left (myList, myNumber) if pos == 0: return myList [0] if pos == len (myList): return myList [-1] before = myList [pos – 1] after = myList [pos] if after – myNumber < myNumber – before: return after else: return before