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How do I find the most frequent words in an array of strings?
How to find the most frequent word in an array of strings
- Given an array of strings, one must find the most frequent word in a given array, i.e., the string that appears the most in the array.
- The most efficient approach to this problem is to use HashMap.
- Implementation.
How do you count repeated strings?
First, we split the string by spaces in a. Then, take a variable count = 0 and in every true condition we increment the count by 1. Now run a loop at 0 to length of string and check if our string is equal to the word.
What word do I use the most?
‘The’ tops the league tables of most frequently used words in English, accounting for 5% of every 100 words used. “’The’ really is miles above everything else,” says Jonathan Culpeper, professor of linguistics at Lancaster University. But why is this?
What’s the maximum repeating value of a string?
For a string sequence, a string word is k -repeating if word concatenated k times is a substring of sequence. The word ‘s maximum k -repeating value is the highest value k where word is k -repeating in sequence. If word is not a substring of sequence, word ‘s maximum k -repeating value is 0.
How to find the maximum number of characters in a string?
First, we declared a Freq array of size 256, which will initially hold 0’s. Next, we used For Loop to iterate every character in a String, and find the maximum repeated character.
How to find the maximum frequency of a word?
After all nodes are inserted into the Trie, perform its preorder traversal ( DFS ), and find the maximum frequency word by comparing the count present at leaf nodes. Note that we can also use a map to solve this problem. Following is the C++, Java, and Python implementation of the idea:
What to do when the count goes beyond the maximum?
If the count goes beyond the current maximum count, we update the result. An efficient solution is to run only one loop. The idea is to reset the count as 1 as soon as we find a character not matching with the previous. This article is contributed by DANISH_RAZA .