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How do I make bash script wait?
wait is typically used in shell scripts that spawn child processes that execute in parallel. To illustrate how the command works, create the following script: #!/bin/bash sleep 30 & process_id=$! echo “PID: $process_id” wait $process_id echo “Exit status: $?”
How do I use shell wait?
wait command is used with a particular process id or job id. When multiple processes are running in the shell then only the process id of the last command will be known by the current shell. If wait command is executed this time, then it will be applied for the last command.
How to use ” wait for all processes ” script?
If you use the following method, you might not need a special “wait for all processes” after the while loop. The loop will wait for the current command1 to complete before it cycles back to top. Please use care as with any advice. Notice, the only thing I did was add & wait $! to the end of your command1. a=1 while [$a -lt 4 ] . command1 & wait $!
How to wait for a command in the background?
I need to make a command in background “command1 &” and then somewhere in the script I need to wait for it to finish before I do command2. Basically, I need this:
How to pause a bash script without an argument?
You’ll want to use the wait command to do this for you. You can either capture all of the children process IDs and wait for them specifically, or if they are the only background processes your script is creating, you can just call wait without an argument. For example:
Is there a way to stop a script within another script?
Is there a way to run a.sh, stop b.sh before it completes (before it prints Bananas) and let a.sh run to completion and print “a is still running”? I have tried putting pkill -f b.sh inside a.sh, but both a.sh and b.sh stop before a.sh completes. At one point, you were close to what you seem to want.