How do you clear the least significant bit?
The use bitwise AND operator & on x to toggle the least significant bit. Another method can be unsigned x = x & 0Xfffffffe which is equal to 11111111111111111111111111111110 i.e 31 bits 1 to keep bit 31 to 1 as it occours in x .
What is the rightmost set bit?
Find the position of the rightmost set bit. The idea is to unset the rightmost bit of number n and XOR the result with n . Then the rightmost set bit in n will be the position of the only set bit in the result. For example, the number 20 in binary is 00010100 , and the position of the rightmost set bit is 3.
What is set bit of XOR?
Any bit <bitwise XOR> Set bit = Toggle which means, 0 ^ 1 = 1 1 ^ 1 = 0. So in order to toggle a bit, performing a bitwise XOR of the number with a reset bit is the best idea.
How do I change my last bit to 0?
Setting a bit means that if K-th bit is 0, then set it to 1 and if it is 1 then leave it unchanged. Clearing a bit means that if K-th bit is 1, then clear it to 0 and if it is 0 then leave it unchanged. Toggling a bit means that if K-th bit is 1, then change it to 0 and if it is 0 then change it to 1.
How to set, clear, clear a single bit?
The XOR operator (^) can be used to toggle a bit. number ^= 1UL << n; That will toggle the n th bit of number.
Which is the best way to clear a number?
So for setting a bit, performing a bitwise OR of the number with a set bit is the best idea. So for clearing a bit, performing a bitwise AND of the number with a reset bit is the best idea. Since XOR of unset and set bit results in a set bit and XOR of a set and set bit results in an unset bit.
How to set, clear and Toggle a given bit of a number?
Input: N = 7, K = 2 Output: Setting Kth bit: 7 Clearing Kth bit: 5 Toggling Kth bit: 5 Explanation: 7 is represented as 111 in binary and has its second bit 1, so setting it will result in 111 i.e. 7. clearing it will result in 101 i.e. 5. toggling it will result in 101 i.e. 5.
How to unset the rightmost set bit of an integer?
Write a program that unsets the rightmost set bit of an integer. Recommended: Please try your approach on {IDE} first, before moving on to the solution. Let the input number be n. n-1 would have all the bits flipped after the rightmost set bit (including the set bit). So, doing n& (n-1) would give us the required result.