How do you count the number of digits in an integer?

How do you count the number of digits in an integer?

Logic to count number of digits in an integer

  1. Input a number from user.
  2. Initialize another variable to store total digits say digit = 0 .
  3. If num > 0 then increment count by 1 i.e. count++ .
  4. Divide num by 10 to remove last digit of the given number i.e. num = num / 10 .
  5. Repeat step 3 to 4 till num > 0 or num !=

How do you divide numbers into digits?

Since the numbers are decimal (base 10), each digit’s range should be 0 to 9.

  1. So, we can get it easy by doing modulo 10. Like,
  2. 12 % 10 => 2 ( we have split the digit 2 from number 12) Now, we have to split the digit 1 from number 12.
  3. 12 / 10 => 1. Now take modulo 10.
  4. 1 % 10 = 1.

How many digits does 2 10000 have?

Now consider 100^2 = 10000 (5 digits) ; 100^3 = 1000000(7 digits).

How do I find the first digit of a number in Python?

When modulo divided by 10 returns its last digit. To finding first digit of a number is little expensive than last digit. To find first digit of a number we divide the given number by 10 until number is greater than 10. At the end we are left with the first digit.

How to count number of digits in an integer?

Count number of digits in an integer without using the loop: We can use log10 (logarithm of base 10) to count the number of digits of positive numbers (logarithm is not defined for negative numbers). Where log10 () is a predefined function present in math.h header file. The total number of digits in a given integer is equal to log10 (num) + 1.

How to find sum of digits in integer?

C program to find sum of digits of any number. C program to find product of digits of any number. C program to swap first and last digits of any number. C program to find sum of first and last digit of any number. Have a doubt, write here. I will help my best.

How to determine the log base of an integer?

The ppc architecture has a bit counting instruction. With that, you can determine the log base 2 of a positive integer in a single instruction. For example, 32 bit would be: If you can handle a small margin of error on large values you can convert that to log base 10 with another few instructions:

How to determine the number of digits in an integer stack?

See Bit Twiddling Hacks for a much shorter version of the answer you accepted. It also has the benefit of finding the answer sooner if your input is normally distributed, by checking the big constants first. (v >= 1000000000) catches 76% of the values, so checking that first will on average be faster.